10x^2+3=95

Solution for 10x^2+3=95 equation:

10x^2+3=95

We move all terms to the left:

10x^2+3-(95)=0

We add all the numbers together, and all the variables

10x^2-92=0

a = 10; b = 0; c = -92;
Δ = b2-4ac
Δ = 02-4·10·(-92)
Δ = 3680
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3680}=\sqrt{16*230}=\sqrt{16}*\sqrt{230}=4\sqrt{230}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{230}}{2*10}=\frac{0-4\sqrt{230}}{20}
=-\frac{4\sqrt{230}}{20}
=-\frac{\sqrt{230}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{230}}{2*10}=\frac{0+4\sqrt{230}}{20}
=\frac{4\sqrt{230}}{20}
=\frac{\sqrt{230}}{5}
$